2x^2+72x-1260=0

Solution for 2x^2+72x-1260=0 equation:

2x^2+72x-1260=0

a = 2; b = 72; c = -1260;
Δ = b2-4ac
Δ = 722-4·2·(-1260)
Δ = 15264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15264}=\sqrt{144*106}=\sqrt{144}*\sqrt{106}=12\sqrt{106}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-12\sqrt{106}}{2*2}=\frac{-72-12\sqrt{106}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+12\sqrt{106}}{2*2}=\frac{-72+12\sqrt{106}}{4}
$